fimplicit
Plot the hyperbola described by the function x2-y2-1=0 over the default interval of
[-5 5]
for x and y.
fimplicit(@(x,y) x.^2 - y.^2 - 1) fig2plotly()
Plot the function x2+y2-3=0 over the intervals
[-3 0]
forx
and[-2 2]
fory
.
f = @(x,y) x.^2 + y.^2 - 3; fimplicit(f,[-3 0 -2 2]) fig2plotly()
Plot two circles centered at
(0,0)
with different radius values. For the first circle, use a dotted, red line. For the second circle, use a dashed, green line with a line width of 2 points.
f1 = @(x,y) x.^2 + y.^2 - 1; fimplicit(f1,':r') hold on f2 = @(x,y) x.^2 + y.^2 - 2; fimplicit(f2,'--g','LineWidth',2) hold off fig2plotly()
Plot the implicit function ysin(x)+xcos(y)-1=0 and assign the implicit function line object to the variable
fp
.
fp = fimplicit(@(x,y) y.*sin(x) + x.*cos(y) - 1) fig2plotly()
fig2plotly()fp = ImplicitFunctionLine with properties: Function: @(x,y)y.*sin(x)+x.*cos(y)-1 Color: [0 0.4470 0.7410] LineStyle: '-' LineWidth: 0.5000 Show all properties
Use
fp
to access and modify properties of the implicit function line object after it is created. For example, change the color, line style, and line width.
fp.Color = 'r'; fp.LineStyle = '--'; fp.LineWidth = 2; fig2plotly()